As distance between two capacitor plates decreases, capacitance increases - given that the dielectric and area of the capacitor plates remain the same. So, why does this occur? As distance between two capacitor plates decreases, capacitance increases - given that the dielectric and area of the capacitor plates remain the same.
As Capacitance C = q/V, C varies with q if V remains the same (connected to a fixed potential elec source). So, with decreased distance q increases, and so C increases. Remember, that for any parallel plate capacitor V is not affected by distance, because: V = W/q (work done per unit charge in bringing it from on plate to the other) and W = F x d
The capacitance of a capacitor reduces with an increase in the space between its two plates. The electrostatic force field that exists between the plates directly relates to the capacitance of the capacitor. As the plates are spaced farther apart, the field gets smaller. Q.
The electrostatic force field that exists between the plates directly relates to the capacitance of the capacitor. As the plates are spaced farther apart, the field gets smaller. Q. What happens to the value of capacitance of a parallel plate capacitor when the distance between the two plates increases?
Capacitors are devices that store energy and exist in a range of shapes and sizes. The expression of the capacitance of a parallel place capacitor is C = ε A d where, ε is the dielectric constant, A the area of the plates, and d the distance between plates. The capacitance of a capacitor reduces with an increase in the space between its two plates.
Two things are happening when the plates are separated while connected to a constant voltage source. First, external mechanical work is being done on the capacitor to move the plates apart against the electrostatic attraction force between the plates. That work adds energy to the capacitor.