Assuming that the diode is ideal and that there is no initial charge on the capacitor, consider what happens to the current through the resistor during the first full cycle of the AC source. In particular, sketch diagrams of the voltage across the resistor and the current through the resistor for a large value of the time constant, RC.
The common wire connecting the lower ends of C and R and the supply, is held at 0V i.e. it is earthed. The AC voltage is V = V max sinωt. Assuming that the diode is ideal and that there is no initial charge on the capacitor, consider what happens to the current through the resistor during the first full cycle of the AC source.
Quick question regarding a circuit containing a diode and capacitor in parallel with each other. In the schematic you can see that in one situation the DC takes the path from terminal 11 to terminal 3 as traced through the green highlight. The voltage is 125 VDC with positive at terminal 11.
There is, however, a fundamental problem with this simple circuit in that when the input signal is less (more negative) than the voltage being held on the capacitor, the diode will be reverse biased and the output of the op amp will be “disconnected” from the inverting input terminal.
A capacitor consists of two conductive plates separated by an insulator. The insulator in a capacitor can be made of materials like ceramic or tantalum. Diodes are pivotal for rectification in power supplies. The diode in the adapter converts the AC input into a DC output. A capacitor is an electronic component that stores electrical charge.
But in the case of high frequency, RF, input signals, the diode capacitance affects the circuit operation adversely and the signal gets attenuated (that is, it passes through diode capacitance to ground). In series clippers, when the diode is in non-conducting state, there will be no transmission of input signal to output.