Figure 8.3.1 8.3. 1: (a) Three capacitors are connected in series. The magnitude of the charge on each plate is Q. (b) The network of capacitors in (a) is equivalent to one capacitor that has a smaller capacitance than any of the individual capacitances in (a), and the charge on its plates is Q.
The series combination of two or three capacitors resembles a single capacitor with a smaller capacitance. Generally, any number of capacitors connected in series is equivalent to one capacitor whose capacitance (called the equivalent capacitance) is smaller than the smallest of the capacitances in the series combination.
Then we can see that if and only if the two series connected capacitors are the same and equal, then the total capacitance, CT will be exactly equal to one half of the capacitance value, that is: C/2.
Find the total capacitance for three capacitors connected in series, given their individual capacitances are 1.000, 5.000, and 8.000 μF. Strategy With the given information, the total capacitance can be found using the equation for capacitance in series. Entering the given capacitances into the expression for 1 CS gives 1 CS = 1 C1 + 1 C2 + 1 C3.
(c) The assumption that the capacitors were hooked up in parallel, rather than in series, was incorrect. A parallel connection always produces a greater capacitance, while here a smaller capacitance was assumed. This could happen only if the capacitors are connected in series.
When capacitors are connected in series, their individual capacitance values contribute to the total equivalent capacitance. The series connection is achieved when the positive plate of one capacitor is connected to the negative plate of the subsequent capacitor. This forms a continuous path for current flow, creating a series circuit.